Multiples of 9 | Sum of the digits | |

9 | 9 | |

18 | 1 + 8 = 9 | |

27 | 2 + 7 = 9 | |

36 | 3 + 6 = 9 | |

45 | 4 + 5 = 9 | |

54 | 5 + 4 = 9 | |

63 | 6 + 3 = 9 | |

72 | 7 + 2 = 9 | |

81 | 8 + 1 = 9 | |

90 | 9 + 0 = 9 | |

99 | 9 + 9 = 18 | 1 + 8 = 9 |

108 | 1 + 0 + 8 = 9 | |

117 | 1 + 1 + 7 = 9 | |

126 | 1 + 2 + 6 = 9 | |

135 | 1 + 3 + 5 = 9 | |

144 | 1 + 4 + 4 = 9 | |

153 | 1 + 5 + 3 = 9 | |

162 | 1 + 6 + 2 = 9 | |

171 | 1 + 7 + 1 = 9 | |

180 | 1 + 8 + 0 = 9 | |

189 | 1 + 8 + 9 = 18 | 1 + 8 = 9 |

198 | 1 + 9 + 8 = 18 | 1 + 8 = 9 |

207 | 2 + 0 + 7 = 9 | |

216 | 2 + 1 + 6 = 9 | |

225 | 2 + 2 + 5 = 9 | |

234 | 2 + 3 + 4 = 9 | |

243 | 2 + 4 + 3 = 9 | |

252 | 2 + 5 + 2 = 9 | |

261 | 2 + 6 + 1 = 9 |

Therefore, we can conclude that

If the sum of the digits of a number is divisible by 9, the number must also divisible by 9or

If the sum of the digits of a number is a multiple of 9, the number must also a multiple of 9.For example:

Is 972635 a multiple of 9?

Sum of the digits:

9 + 7 + 2 + 6 + 3 + 5 = 32

32 is not multiple of 9, hence 972635 is not a multiple of 9.

Let's see another example:

Is 683746533 divisible by 9?

Sum of the digits:

6 + 8 + 3 + 7 + 4 + 6 + 5 + 3 + 3 = 45

45 is divisible by 9, hence 683746533 is divisible by 9

## 0 comments:

## Post a Comment