Multiples of 9 | Sum of the digits | |
9 | 9 | |
18 | 1 + 8 = 9 | |
27 | 2 + 7 = 9 | |
36 | 3 + 6 = 9 | |
45 | 4 + 5 = 9 | |
54 | 5 + 4 = 9 | |
63 | 6 + 3 = 9 | |
72 | 7 + 2 = 9 | |
81 | 8 + 1 = 9 | |
90 | 9 + 0 = 9 | |
99 | 9 + 9 = 18 | 1 + 8 = 9 |
108 | 1 + 0 + 8 = 9 | |
117 | 1 + 1 + 7 = 9 | |
126 | 1 + 2 + 6 = 9 | |
135 | 1 + 3 + 5 = 9 | |
144 | 1 + 4 + 4 = 9 | |
153 | 1 + 5 + 3 = 9 | |
162 | 1 + 6 + 2 = 9 | |
171 | 1 + 7 + 1 = 9 | |
180 | 1 + 8 + 0 = 9 | |
189 | 1 + 8 + 9 = 18 | 1 + 8 = 9 |
198 | 1 + 9 + 8 = 18 | 1 + 8 = 9 |
207 | 2 + 0 + 7 = 9 | |
216 | 2 + 1 + 6 = 9 | |
225 | 2 + 2 + 5 = 9 | |
234 | 2 + 3 + 4 = 9 | |
243 | 2 + 4 + 3 = 9 | |
252 | 2 + 5 + 2 = 9 | |
261 | 2 + 6 + 1 = 9 |
Therefore, we can conclude that
If the sum of the digits of a number is divisible by 9, the number must also divisible by 9or
If the sum of the digits of a number is a multiple of 9, the number must also a multiple of 9.For example:
Is 972635 a multiple of 9?
Sum of the digits:
9 + 7 + 2 + 6 + 3 + 5 = 32
32 is not multiple of 9, hence 972635 is not a multiple of 9.
Let's see another example:
Is 683746533 divisible by 9?
Sum of the digits:
6 + 8 + 3 + 7 + 4 + 6 + 5 + 3 + 3 = 45
45 is divisible by 9, hence 683746533 is divisible by 9
0 comments:
Post a Comment